Uniform Limit Theorem
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In
mathematics Mathematics is an area of knowledge that includes the topics of numbers, formulas and related structures, shapes and the spaces in which they are contained, and quantities and their changes. These topics are represented in modern mathematics ...
, the uniform limit theorem states that the
uniform limit In the mathematical field of analysis, uniform convergence is a mode of convergence of functions stronger than pointwise convergence. A sequence of functions (f_n) converges uniformly to a limiting function f on a set E if, given any arbitrarily s ...
of any sequence of
continuous function In mathematics, a continuous function is a function such that a continuous variation (that is a change without jump) of the argument induces a continuous variation of the value of the function. This means that there are no abrupt changes in value ...
s is continuous.


Statement

More precisely, let ''X'' be a
topological space In mathematics, a topological space is, roughly speaking, a geometrical space in which closeness is defined but cannot necessarily be measured by a numeric distance. More specifically, a topological space is a set whose elements are called points ...
, let ''Y'' be a
metric space In mathematics, a metric space is a set together with a notion of ''distance'' between its elements, usually called points. The distance is measured by a function called a metric or distance function. Metric spaces are the most general settin ...
, and let ƒ''n'' : ''X'' → ''Y'' be a sequence of functions converging uniformly to a function ƒ : ''X'' → ''Y''. According to the uniform limit theorem, if each of the functions ƒ''n'' is continuous, then the limit ƒ must be continuous as well. This theorem does not hold if uniform convergence is replaced by
pointwise convergence In mathematics, pointwise convergence is one of various senses in which a sequence of functions can converge to a particular function. It is weaker than uniform convergence, to which it is often compared. Definition Suppose that X is a set and ...
. For example, let ƒ''n'' :  , 1nbsp;→ R be the sequence of functions ƒ''n''(''x'') = ''xn''. Then each function ƒ''n'' is continuous, but the sequence converges pointwise to the discontinuous function ƒ that is zero on , 1)_but_has_ƒ(1) = 1.__Another_example_is_shown_in_the_adjacent_image. In_terms_of_function_spaces,_the_uniform_limit_theorem_says_that_the_space_''C''(''X'', ''Y'')_of_all_continuous_functions_from_a_topological_space_''X''_to_a_metric_space_''Y''_is_a_closed_set.html" ;"title="function_space.html" ;"title=", 1) but has ƒ(1) = 1. Another example is shown in the adjacent image. In terms of function space">, 1) but has ƒ(1) = 1. Another example is shown in the adjacent image. In terms of function spaces, the uniform limit theorem says that the space ''C''(''X'', ''Y'') of all continuous functions from a topological space ''X'' to a metric space ''Y'' is a closed set">closed subset of ''YX'' under the uniform metric. In the case where ''Y'' is Complete metric space, complete, it follows that ''C''(''X'', ''Y'') is itself a complete metric space. In particular, if ''Y'' is a Banach space, then ''C''(''X'', ''Y'') is itself a Banach space under the
uniform norm In mathematical analysis, the uniform norm (or ) assigns to real- or complex-valued bounded functions defined on a set the non-negative number :\, f\, _\infty = \, f\, _ = \sup\left\. This norm is also called the , the , the , or, when th ...
. The uniform limit theorem also holds if continuity is replaced by
uniform continuity In mathematics, a real function f of real numbers is said to be uniformly continuous if there is a positive real number \delta such that function values over any function domain interval of the size \delta are as close to each other as we want. In ...
. That is, if ''X'' and ''Y'' are metric spaces and ƒ''n'' : ''X'' → ''Y'' is a sequence of uniformly continuous functions converging uniformly to a function ƒ, then ƒ must be uniformly continuous.


Proof

In order to prove the continuity of ''f'', we have to show that for every ''ε'' > 0, there exists a
neighbourhood A neighbourhood (British English, Irish English, Australian English and Canadian English) or neighborhood (American English; see spelling differences) is a geographically localised community within a larger city, town, suburb or rural are ...
''U'' of any point ''x'' of ''X'' such that: :d_Y(f(x),f(y)) < \varepsilon, \qquad\forall y \in U Consider an arbitrary ''ε'' > 0. Since the sequence of functions ''(fn)'' converges uniformly to ''f'' by hypothesis, there exists a natural number ''N'' such that: :d_Y(f_N(t),f(t)) < \frac, \qquad\forall t \in X Moreover, since ''fN'' is continuous on ''X'' by hypothesis, for every ''x'' there exists a neighbourhood ''U'' such that: :d_Y(f_N(x),f_N(y)) < \frac, \qquad\forall y \in U In the final step, we apply the
triangle inequality In mathematics, the triangle inequality states that for any triangle, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side. This statement permits the inclusion of degenerate triangles, but ...
in the following way: :\begin d_Y(f(x),f(y)) & \leq d_Y(f(x),f_N(x)) + d_Y(f_N(x),f_N(y)) + d_Y(f_N(y),f(y)) \\ & < \frac + \frac + \frac = \varepsilon, \qquad \forall y \in U \end Hence, we have shown that the first inequality in the proof holds, so by definition ''f'' is continuous everywhere on ''X''.


Uniform limit theorem in complex analysis

There are also variants of the uniform limit theorem that are used in complex analysis, albeit with modified assumptions. Theorem. Let \Omega be an open and connected subset of the complex numbers. Suppose that (f_n)_^ is a sequence of holomorphic functions f_n:\Omega\to \mathbb that converges uniformly to a function f:\Omega \to \mathbb on every compact subset of \Omega. Then f is holomorphic in \Omega, and moreover, the sequence of derivatives (f'_n)_^ converges uniformly to f' on every compact subset of \Omega. Theorem. Let \Omega be an open and connected subset of the complex numbers. Suppose that (f_n)_^ is a sequence of univalentUnivalent means holomorphic and injective. functions f_n:\Omega\to \mathbb that converges uniformly to a function f:\Omega \to \mathbb. Then f is holomorphic, and moreover, f is either univalent or constant in \Omega.


Notes


References

* {{cite book , author = James Munkres , author-link = James Munkres , year = 1999 , title = Topology , edition = 2nd , publisher =
Prentice Hall Prentice Hall was an American major educational publisher owned by Savvas Learning Company. Prentice Hall publishes print and digital content for the 6–12 and higher-education market, and distributes its technical titles through the Safari B ...
, isbn = 0-13-181629-2 * E. M. Stein, R. Shakarachi (2003). ''Complex Analysis (Princeton Lectures in Analysis, No. 2)'', Princeton University Press, pp.53-54. * E. C. Titchmarsh (1939). ''The Theory of Functions'', 2002 Reprint, Oxford Science Publications. Theorems in real analysis Topology of function spaces