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In mathematical analysis, the Young's inequality for integral operators, is a bound on the L^p\to L^q operator norm of an integral operator in terms of L^r norms of the kernel itself.


Statement

Assume that X and Y are measurable spaces, K : X \times Y \to \mathbb is measurable and q,p,r\geq 1 are such that \frac = \frac + \frac -1. If : \int_ , K (x, y), ^r \,\mathrm y \le C^r for all x\in X and : \int_ , K (x, y), ^r \,\mathrm x \le C^r for all y\in Y then Theorem 0.3.1 in: C. D. Sogge, ''Fourier integral in classical analysis'', Cambridge University Press, 1993. : \int_ \left, \int_ K (x, y) f(y) \,\mathrm y\^q \, \mathrm x \le C^q \left( \int_ , f(y), ^p \,\mathrm y\right)^\frac.


Particular cases


Convolution kernel

If X = Y = \mathbb^d and K (x, y) = h (x - y) , then the inequality becomes
Young's convolution inequality In mathematics, Young's convolution inequality is a mathematical inequality about the convolution of two functions, named after William Henry Young. Statement Euclidean Space In real analysis, the following result is called Young's convolution ...
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See also

Young's inequality for products In mathematics, Young's inequality for products is a mathematical inequality about the product of two numbers. The inequality is named after William Henry Young and should not be confused with Young's convolution inequality. Young's inequality f ...


Notes

Inequalities {{mathanalysis-stub