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In mathematics, the Mertens conjecture is the statement that the Mertens function M(n) is bounded by \pm\sqrt. Although now disproven, it had been shown to imply the Riemann hypothesis. It was conjectured by Thomas Joannes Stieltjes, in an 1885 letter to
Charles Hermite Charles Hermite () FRS FRSE MIAS (24 December 1822 – 14 January 1901) was a French mathematician who did research concerning number theory, quadratic forms, invariant theory, orthogonal polynomials, elliptic functions, and algebra. Hermite p ...
(reprinted in ), and again in print by , and disproved by . It is a striking example of a mathematical conjecture proven false despite a large amount of computational evidence in its favor.


Definition

In number theory, we define the Mertens function as : M(n) = \sum_ \mu(k), where μ(k) is the Möbius function; the Mertens conjecture is that for all ''n'' > 1, : , M(n), < \sqrt.


Disproof of the conjecture

Stieltjes claimed in 1885 to have proven a weaker result, namely that m(n) := M(n)/\sqrt was bounded, but did not publish a proof. (In terms of m(n), the Mertens conjecture is that -1 < m(n) < 1 .) In 1985,
Andrew Odlyzko Andrew Michael Odlyzko (Andrzej Odłyżko) (born 23 July 1949) is a Polish- American mathematician and a former head of the University of Minnesota's Digital Technology Center and of the Minnesota Supercomputing Institute. He began his career in ...
and
Herman te Riele Hermanus Johannes Joseph te Riele (born 5 January 1947) is a Dutch mathematician at CWI in Amsterdam with a specialization in computational number theory. He is known for proving the correctness of the Riemann hypothesis for the first 1.5 billi ...
proved the Mertens conjecture false using the Lenstra–Lenstra–Lovász lattice basis reduction algorithm:Sandor et al (2006) pp. 188–189. : \liminf m(n) < -1.009 and \limsup m(n) > 1.06. It was later shown that the first
counterexample A counterexample is any exception to a generalization. In logic a counterexample disproves the generalization, and does so rigorously in the fields of mathematics and philosophy. For example, the fact that "John Smith is not a lazy student" is a ...
appears below e^ \approx 10^ but above 1016. The upper bound has since been lowered to e^ or approximately 10^, but no ''explicit'' counterexample is known. The law of the iterated logarithm states that if is replaced by a random sequence of +1s and −1s then the order of growth of the partial sum of the first terms is (with probability 1) about which suggests that the order of growth of might be somewhere around . The actual order of growth may be somewhat smaller; in the early 1990s Steve Gonek conjectured that the order of growth of was (\log\log\log n)^, which was affirmed by Ng (2004), based on a heuristic argument, that assumed the Riemann hypothesis and certain conjectures about the averaged behavior of zeros of the Riemann zeta function. In 1979, Cohen and Dress found the largest known value of m(n) \approx 0.570591 for and in 2011, Kuznetsov found the largest known negative value m(n) \approx -0.585768 for In 2016, Hurst computed for every but did not find larger values of . In 2006, Kotnik and te Riele improved the upper bound and showed that there are infinitely many values of for which but without giving any specific value for such an .Kotnik & te Riele (2006). In 2016, Hurst made further improvements by showing : \liminf m(n) < -1.837625 and \limsup m(n) > 1.826054.


Connection to the Riemann hypothesis

The connection to the Riemann hypothesis is based on the
Dirichlet series In mathematics, a Dirichlet series is any series of the form \sum_^\infty \frac, where ''s'' is complex, and a_n is a complex sequence. It is a special case of general Dirichlet series. Dirichlet series play a variety of important roles in ana ...
for the reciprocal of the Riemann zeta function, :\frac = \sum_^\infty \frac, valid in the region \mathcal(s) > 1. We can rewrite this as a Stieltjes integral :\frac = \int_0^\infty x^ dM(x) and after integrating by parts, obtain the reciprocal of the zeta function as a Mellin transform :\frac = \left\(-s) = \int_0^\infty x^ M(x)\, \frac. Using the Mellin inversion theorem we now can express in terms of as :M(x) = \frac \int_^ \frac\,ds which is valid for , and valid for on the Riemann hypothesis. From this, the Mellin transform integral must be convergent, and hence must be for every exponent ''e'' greater than . From this it follows that :M(x) = O\Big(x^\Big) for all positive is equivalent to the Riemann hypothesis, which therefore would have followed from the stronger Mertens hypothesis, and follows from the hypothesis of Stieltjes that :M(x) = O\Big(x^\tfrac\Big).


References


Further reading

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External links

* {{Authority control Analytic number theory Disproved conjectures