In mathematics, specifically the theory of
Lie algebra
In mathematics, a Lie algebra (pronounced ) is a vector space \mathfrak g together with an Binary operation, operation called the Lie bracket, an Alternating multilinear map, alternating bilinear map \mathfrak g \times \mathfrak g \rightarrow ...
s, Lie's theorem states that,
over an algebraically closed field of characteristic zero, if
is a finite-dimensional
representation of a
solvable Lie algebra
In mathematics, a Lie algebra \mathfrak is solvable if its derived series terminates in the zero subalgebra. The ''derived Lie algebra'' of the Lie algebra \mathfrak is the subalgebra of \mathfrak, denoted
: mathfrak,\mathfrak/math>
that consist ...
, then there's a
flag
A flag is a piece of fabric (most often rectangular or quadrilateral) with a distinctive design and colours. It is used as a symbol, a signalling device, or for decoration. The term ''flag'' is also used to refer to the graphic design empl ...
of
invariant subspaces of
with
, meaning that
for each
and ''i''.
Put in another way, the theorem says there is a basis for ''V'' such that all linear transformations in
are represented by upper triangular matrices. This is a generalization of the result of Frobenius that
commuting matrices In linear algebra, two matrices A and B are said to commute if AB=BA, or equivalently if their commutator ,B AB-BA is zero. A set of matrices A_1, \ldots, A_k is said to commute if they commute pairwise, meaning that every pair of matrices in the s ...
are simultaneously
upper triangularizable, as commuting matrices generate an
abelian Lie algebra
In mathematics, a Lie algebra (pronounced ) is a vector space \mathfrak g together with an operation called the Lie bracket, an alternating bilinear map \mathfrak g \times \mathfrak g \rightarrow \mathfrak g, that satisfies the Jacobi ident ...
, which is a fortiori solvable.
A consequence of Lie's theorem is that any finite dimensional solvable Lie algebra over a field of characteristic 0 has a nilpotent
derived algebra
In mathematics, a Lie algebra \mathfrak is solvable if its derived series terminates in the zero subalgebra. The ''derived Lie algebra'' of the Lie algebra \mathfrak is the subalgebra of \mathfrak, denoted
: mathfrak,\mathfrak/math>
that consi ...
(see
#Consequences). Also, to each flag in a finite-dimensional vector space ''V'', there correspond a
Borel subalgebra In mathematics, specifically in representation theory, a Borel subalgebra of a Lie algebra \mathfrak is a maximal solvable subalgebra. The notion is named after Armand Borel.
If the Lie algebra \mathfrak is the Lie algebra of a complex Lie group, ...
(that consist of linear transformations stabilizing the flag); thus, the theorem says that
is contained in some Borel subalgebra of
.
Counter-example
For algebraically closed fields of characteristic ''p''>0 Lie's theorem holds provided the dimension of the representation is less than ''p'' (see the proof below), but can fail for representations of dimension ''p''. An example is given by the 3-dimensional nilpotent Lie algebra spanned by 1, ''x'', and ''d''/''dx'' acting on the ''p''-dimensional vector space ''k''
'x''(''x''
''p''), which has no eigenvectors. Taking the semidirect product of this 3-dimensional Lie algebra by the ''p''-dimensional representation (considered as an abelian Lie algebra) gives a solvable Lie algebra whose derived algebra is not nilpotent.
Proof
The proof is by induction on the dimension of
and consists of several steps. (Note: the structure of the proof is very similar to that for
Engel's theorem
In representation theory, a branch of mathematics, Engel's theorem states that a finite-dimensional Lie algebra \mathfrak g is a nilpotent Lie algebra_if_and_only_if_for_each_X_\in_\mathfrak_g,_the_adjoint_representation_of_a_Lie_algebra.html" "ti ...
.) The basic case is trivial and we assume the dimension of
is positive. We also assume ''V'' is not zero. For simplicity, we write
.
Step 1: Observe that the theorem is equivalent to the statement:
*There exists a vector in ''V'' that is an eigenvector for each linear transformation in
.
Indeed, the theorem says in particular that a nonzero vector spanning
is a common eigenvector for all the linear transformations in
. Conversely, if ''v'' is a common eigenvector, take
to its span and then
admits a common eigenvector in the quotient
; repeat the argument.
Step 2: Find an ideal
of codimension one in
.
Let
.
*Lie–Kolchin_theorem,_which_is_about_a_(connected)_solvable_linear_algebraic_group.