Cotlar–Stein Lemma

In mathematics, in the field of functional analysis, the Cotlar–Stein almost orthogonality lemma is named after mathematicians Mischa Cotlar
and Elias Stein. It may be used to obtain information on the operator norm on an operator, acting from one Hilbert space into another
when the operator can be decomposed into ''almost orthogonal'' pieces.
The original version of this lemma
(for self-adjoint and mutually commuting operators)
was proved by Mischa Cotlar in 1955 and allowed him to conclude that the Hilbert transform
is a continuous linear operator in $L^2$
without using the Fourier transform.
A more general version was proved by Elias Stein.

Cotlar–Stein almost orthogonality lemma

Let $E,\,F$ be two Hilbert spaces.
Consider a family of operators
$T_j$, $j\geq 1$,
with each $T_j$
a bounded linear operator from $E$ to $F$.

Denote

: $a_=\Vert T_j T_k^\ast\Vert, \qquad b_=\Vert T_j^\ast T_k\Vert.$

The family of operators
$T_j:\;E\to F$, $j\ge 1,$
is ''almost orthogonal'' if

:$A=\sup_\sum_\sqrt<\infty, \qquad B=\sup_\sum_\sqrt<\infty.$

The Cotlar–Stein lemma states that if $T_j$
are almost orthogonal,
then the series
$\sum_T_j$
converges in the strong operator topology,
and that

:$\Vert \sum_T_j\Vert \le\sqrt.$

Proof

If ''R''₁, ..., ''R''_''n'' is a finite collection of bounded operators, then

:$\displaystyle$

So under the hypotheses of the lemma,

:$\displaystyle$

It follows that

:$\displaystyle$

and that

:$\displaystyle$

Hence the partial sums

:$\displaystyle$

form a Cauchy sequence.

The sum is therefore absolutely convergent with limit satisfying the stated inequality.

To prove the inequality above set

:$\displaystyle$

with , ''a''_''ij'', ≤ 1 chosen so that

:$\displaystyle$

Then

:$\displaystyle$

Hence

:$\displaystyle$

Taking 2''m''th roots and letting ''m'' tend to ∞,

:$\displaystyle$

which immediately implies the inequality.

Generalization

There is a generalization of the Cotlar–Stein lemma with sums replaced by integrals. Let ''X'' be a locally compact space and μ a Borel measure on ''X''. Let ''T''(''x'') be a map from ''X'' into bounded operators from ''E'' to ''F'' which is uniformly bounded and continuous in the strong operator topology. If

:$\displaystyle$

are finite, then the function ''T''(''x'')''v'' is integrable for each ''v'' in ''E'' with

:$\displaystyle$

The result can be proved by replacing sums by integrals in the previous proof or by using Riemann sums to approximate the integrals.

Example

Here is an example of an ''orthogonal'' family of operators. Consider the inifite-dimensional matrices

:
T=\left \begin
1&0&0&\vdots\\0&1&0&\vdots\\0&0&1&\vdots\\\cdots&\cdots&\cdots&\ddots\end
\right

and also

:
\qquad
T_1=\left \begin
1&0&0&\vdots\\0&0&0&\vdots\\0&0&0&\vdots\\\cdots&\cdots&\cdots&\ddots\end
\right
\qquad
T_2=\left \begin
0&0&0&\vdots\\0&1&0&\vdots\\0&0&0&\vdots\\\cdots&\cdots&\cdots&\ddots\end
\right
\qquad
T_3=\left \begin
0&0&0&\vdots\\0&0&0&\vdots\\0&0&1&\vdots\\\cdots&\cdots&\cdots&\ddots\end
\right
\qquad
\dots.

Then
$\Vert T_j\Vert=1$ for each $j$,
hence the series $\sum_T_j$
does not converge in the uniform operator topology.

Yet, since
$\Vert T_j T_k^\ast\Vert=0$
and
$\Vert T_j^\ast T_k\Vert=0$
for $j\ne k$,
the Cotlar–Stein almost orthogonality lemma tells us that

:$T=\sum_T_j$

converges in the strong operator topology and is bounded by 1.

Notes

References

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{{DEFAULTSORT:Cotlar-Stein lemma
Hilbert spaces
Harmonic analysis
Operator theory
Inequalities
Theorems in functional analysis
Lemmas in analysis