Airglow In Auvergne (France) On 13th Of August 2015

Airglow (also called nightglow) is a faint emission of light by a planetary atmosphere. In the case of Earth's atmosphere, this optical phenomenon causes the night sky never to be completely dark, even after the effects of starlight and diffused sunlight from the far side are removed. This phenomenon originates with self-illuminated gases and has no relationship with Earth's magnetism or sunspot activity.

History

The airglow phenomenon was first identified in 1868 by Swedish physicist Anders Ångström. Since then, it has been studied in the laboratory, and various chemical reactions have been observed to emit electromagnetic energy as part of the process. Scientists have identified some of those processes that would be present in Earth's atmosphere, and astronomers have verified that such emissions are present. Simon Newcomb was the first person to scientifically study and describe airglow, in 1901

Airglow existed in pre-industrial society and was known to the ancient Greeks. "Aristotle and Pliny described the phenomena of ''Chasmata'', which can be identified in part as auroras, and in part as bright airglow nights."Google Books: SCIENCES OF THE EARTH, An Encyclopedia of Events, People, and Phenomena, 1998, Garland Publishing, PAGE 3
Google Books
access date 25 June 2022.

Description

Airglow is caused by various processes in the upper atmosphere of Earth, such as the recombination of atoms which were photoionized by the Sun during the day, luminescence caused by cosmic rays striking the upper atmosphere, and chemiluminescence caused mainly by oxygen and nitrogen reacting with hydroxyl free radicals at heights of a few hundred kilometres. It is not noticeable during the daytime due to the glare and scattering of sunlight.

Even at the best ground-based observatories, airglow limits the photosensitivity of optical telescopes. Partly for this reason, space telescopes like Hubble can observe much fainter objects than current ground-based telescopes at visible wavelengths.

Airglow at night may be bright enough for a ground observer to notice and appears generally bluish. Although airglow emission is fairly uniform across the atmosphere, it appears brightest at about 10° above the observer's horizon, since the lower one looks, the greater the mass of atmosphere one is looking through. Very low down, however, atmospheric extinction reduces the apparent brightness of the airglow.

One airglow mechanism is when an atom of nitrogen combines with an atom of oxygen to form a molecule of nitric oxide (NO). In the process, a photon is emitted. This photon may have any of several different wavelengths characteristic of nitric oxide molecules. The free atoms are available for this process, because molecules of nitrogen (N₂) and oxygen (O₂) are dissociated by solar energy in the upper reaches of the atmosphere and may encounter each other to form NO. Other chemicals that can create air glow in the atmosphere are hydroxyl (OH),


atomic oxygen (O), sodium (Na), and lithium (Li).

The sky brightness is typically measured in units of apparent magnitude per square arcsecond of sky.

Calculation

In order to calculate the relative intensity of airglow, we need to convert apparent magnitudes into fluxes of photons; this clearly depends on the spectrum of the source, but we will ignore that initially. At visible wavelengths, we need the parameter S₀(V), the power per square centimetre of aperture and per micrometre of wavelength produced by a zeroth-magnitude star, to convert apparent magnitudes into fluxes – . If we take the example of a ''V''=28 star observed through a normal ''V'' band filter ( bandpass, frequency ), the number of photons we receive per square centimeter of telescope aperture per second from the source is ''N''_''s'':

:$N_s = 10^\times\frac$

(where ''h'' is Planck's constant; ''hν'' is the energy of a single photon of frequency ''ν'').

At ''V'' band, the emission from airglow is per square arc-second at a high-altitude observatory on a moonless night; in excellent seeing conditions, the image of a star will be about 0.7 arc-second across with an area of 0.4 square arc-second, and so the emission from airglow over the area of the image corresponds to about . This gives the number of photons from airglow, ''N''_''a'':

:$N_a = 10^\times\frac$

The signal-to-noise for an ideal ground-based observation with a telescope of area ''A'' (ignoring losses and detector noise), arising from Poisson statistics, is only:

:$S/N = \sqrt\times\frac$

If we assume a 10 m diameter ideal ground-based telescope and an unresolved star: every second, over a patch the size of the seeing-enlarged image of the star, 35 photons arrive from the star and 3500 from air-glow. So, over an hour, roughly arrive from the air-glow, and approximately arrive from the source; so the S/N ratio is about:

:$\frac \approx 36.$

We can compare this with "real" answers from exposure time calculators. For an 8 m unit Very Large Telescope telescope, according to th
FORS
exposure time calculator, 40 hours of observing time are needed to reach ''V'' = 28, while the 2.4 m Hubble only takes 4 hours according to th
ACS
exposure time calculator. A hypothetical 8 m Hubble telescope would take about 30 minutes.

It should be clear from this calculation that reducing the view field size can make fainter objects more detectable against the airglow; unfortunately, adaptive optics techniques that reduce the diameter of the view field of an Earth-based telescope by an order of magnitude only as yet work in the infrared, where the sky is much brighter. A space telescope isn't restricted by the view field, since it is not affected by airglow.

Induced airglow

Scientific experiments have been conducted to induce airglow by directing high-power radio emissions at the Earth's ionosphere.