In
algebraic geometry, a morphism
between
schemes is said to be smooth if
*(i) it is
locally of finite presentation
*(ii) it is
flat, and
*(iii) for every
geometric point the fiber
is regular.
(iii) means that each geometric fiber of ''f'' is a
nonsingular variety (if it is separated). Thus, intuitively speaking, a smooth morphism gives a flat family of nonsingular varieties.
If ''S'' is the
spectrum
A spectrum (plural ''spectra'' or ''spectrums'') is a condition that is not limited to a specific set of values but can vary, without gaps, across a continuum. The word was first used scientifically in optics to describe the rainbow of color ...
of an algebraically closed
field and ''f'' is of finite type, then one recovers the definition of a nonsingular variety.
Equivalent definitions
There are many equivalent definitions of a smooth morphism. Let
be locally of finite presentation. Then the following are equivalent.
# ''f'' is smooth.
# ''f'' is formally smooth (see below).
# ''f'' is flat and the
sheaf of relative differentials is locally free of rank equal to the
relative dimension of
.
# For any
, there exists a neighborhood
of x and a neighborhood
of
such that
and the ideal generated by the ''m''-by-''m'' minors of
is ''B''.
# Locally, ''f'' factors into
where ''g'' is étale.
# Locally, ''f'' factors into
where ''g'' is étale.
A morphism of finite type is
étale if and only if it is smooth and
quasi-finite.
A smooth morphism is stable under base change and composition.
A smooth morphism is universally
locally acyclic.
Examples
Smooth morphisms are supposed to geometrically correspond to smooth
submersions in differential geometry; that is, they are smooth locally trivial fibrations over some base space (by
Ehresmann's theorem
In mathematics, or specifically, in differential topology, Ehresmann's lemma or Ehresmann's fibration theorem states that if a smooth mapping f\colon M \rightarrow N, where M and N are smooth manifolds, is
# a surjective submersion, and
# a pro ...
).
Smooth Morphism to a Point
Let
be the morphism of schemes
:
It is smooth because of the Jacobian condition: the Jacobian matrix
:
vanishes at the points
which has an empty intersection with the polynomial, since
:
which are both non-zero.
Trivial Fibrations
Given a smooth scheme
the projection morphism
:
is smooth.
Vector Bundles
Every vector bundle
over a scheme is a smooth morphism. For example, it can be shown that the associated vector bundle of
over
is the weighted projective space minus a point
:
sending
: