Integration by reduction formulae
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In integral calculus, integration by reduction formulae is method relying on
recurrence relation In mathematics, a recurrence relation is an equation according to which the nth term of a sequence of numbers is equal to some combination of the previous terms. Often, only k previous terms of the sequence appear in the equation, for a parameter ...
s. It is used when an expression containing an
integer An integer is the number zero (), a positive natural number (, , , etc.) or a negative integer with a minus sign ( −1, −2, −3, etc.). The negative numbers are the additive inverses of the corresponding positive numbers. In the languag ...
parameter A parameter (), generally, is any characteristic that can help in defining or classifying a particular system (meaning an event, project, object, situation, etc.). That is, a parameter is an element of a system that is useful, or critical, when ...
, usually in the form of powers of elementary functions, or
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s of
transcendental function In mathematics, a transcendental function is an analytic function that does not satisfy a polynomial equation, in contrast to an algebraic function. In other words, a transcendental function "transcends" algebra in that it cannot be expressed ...
s and
polynomial In mathematics, a polynomial is an expression consisting of indeterminates (also called variables) and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables. An exampl ...
s of arbitrary degree, can't be integrated directly. But using other methods of integration a reduction formula can be set up to obtain the integral of the same or similar expression with a lower integer parameter, progressively simplifying the integral until it can be evaluated. This method of integration is one of the earliest used.


How to find the reduction formula

The reduction formula can be derived using any of the common methods of integration, like
integration by substitution In calculus, integration by substitution, also known as ''u''-substitution, reverse chain rule or change of variables, is a method for evaluating integrals and antiderivatives. It is the counterpart to the chain rule for differentiation, and ...
,
integration by parts In calculus, and more generally in mathematical analysis, integration by parts or partial integration is a process that finds the integral of a product of functions in terms of the integral of the product of their derivative and antiderivat ...
, integration by trigonometric substitution, integration by partial fractions, etc. The main idea is to express an integral involving an integer parameter (e.g. power) of a function, represented by In, in terms of an integral that involves a lower value of the parameter (lower power) of that function, for example ''I''''n''-1 or ''I''''n''-2. This makes the reduction formula a type of
recurrence relation In mathematics, a recurrence relation is an equation according to which the nth term of a sequence of numbers is equal to some combination of the previous terms. Often, only k previous terms of the sequence appear in the equation, for a parameter ...
. In other words, the reduction formula expresses the integral :I_n =\int f(x,n) \,\textx, in terms of :I_k = \int f(x,k) \,\textx, where :k < n.


How to compute the integral

To compute the integral, we set ''n'' to its value and use the reduction formula to express it in terms of the (''n'' – 1) or (''n'' – 2) integral. The lower index integral can be used to calculate the higher index ones; the process is continued repeatedly until we reach a point where the function to be integrated can be computed, usually when its index is 0 or 1. Then we back-substitute the previous results until we have computed ''In''.


Examples

Below are examples of the procedure.


Cosine integral

Typically, integrals like :\int \cos^n x \,\textx , \,\! can be evaluated by a reduction formula. Start by setting: :I_n = \int \cos^n x\,\textx . \,\! Now re-write as: :I_n = \int \cos^ x \cos x \,\textx , \,\! Integrating by this substitution: :\cos x \,\textx = \text ( \sin x) , \,\! :I_n = \int \cos^ x \,\text(\sin x) . \! Now integrating by parts: : \begin \int \cos^n x \,\textx & = \cos^ x \sin x - \int \sin x \,\text(\cos^ x) \\ & = \cos^ x \sin x + (n-1) \int \sin x \cos^ x\sin x \,\textx\\ & = \cos^ x \sin x + (n-1) \int \cos^ x \sin^2 x \,\textx\\ & = \cos^ x \sin x + (n-1) \int \cos^ x (1-\cos^2 x )\,\textx\\ & = \cos^ x \sin x + (n-1) \int \cos^ x \,\textx - (n-1)\int \cos^n x \,\textx\\ & = \cos^ x \sin x + (n-1) I_ - (n-1) I_n , \end \, solving for ''In'': :I_n \ + (n-1) I_n\ = \cos^ x \sin x\ + \ (n-1) I_ , \, :n I_n\ = \cos^ (x) \sin x\ + (n-1) I_ , \, :I_n \ = \frac\cos^ x \sin x\ + \frac I_ , \, so the reduction formula is: :\int \cos^n x \,\textx\ = \frac\cos^ x \sin x + \frac \int \cos^ x \,\textx . \! To supplement the example, the above can be used to evaluate the integral for (say) ''n'' = 5; : I_5 = \int \cos^5 x \,\textx . \,\! Calculating lower indices: :n=5, \quad I_5 = \tfrac \cos^4 x \sin x + \tfrac I_3 , \, :n=3, \quad I_3 = \tfrac \cos^2 x \sin x + \tfrac I_1, \, back-substituting: :\because I_1\ = \int \cos x \,\textx = \sin x + C_1,\, :\therefore I_3\ = \tfrac \cos^2 x \sin x + \tfrac\sin x + C_2, \quad C_2\ = \tfrac C_1,\, :I_5\ = \frac \cos^4 x \sin x + \frac\left frac \cos^2 x \sin x + \frac \sin x\right+ C,\, where ''C'' is a constant.


Exponential integral

Another typical example is: :\int x^n e^ \,\textx . \,\! Start by setting: :I_n = \int x^n e^ \,\textx . \,\! Integrating by substitution: : x^n \,\textx = \frac , \,\! :I_n = \frac \int e^ \,\text(x^) , \! Now integrating by parts: :\begin \int e^ \,\text(x^) & = x^e^ - \int x^ \,\text(e^) \\ & = x^e^ - a \int x^ e^\,\textx , \end \! :(n+1) I_n = x^e^ - a I_ , \! shifting indices back by 1 (so ''n + 1'' → ''n'', ''n'' → ''n'' – 1): :n I_ = x^ne^ - a I_n , \! solving for ''In'': : I_n = \frac \left ( x^ne^ - n I_ \right ) , \,\! so the reduction formula is: : \int x^n e^ \,\textx = \frac \left ( x^ne^ - n \int x^ e^ \,\textx \right ). \! An alternative way in which the derivation could be done starts by substituting e^. Integration by substitution: e^ \,\textx = \frac , \,\! I_n = \frac \int x^ \,\text(e^) , \! Now integrating by parts: \begin \int x^ \,\text(e^) & = x^e^ - \int e^ \,\text(x^) \\ & = x^e^ - n \int e^ x^\,\textx , \end \! which gives the reduction formula when substituting back: I_n = \frac \left ( x^ne^ - n I_ \right ) , \,\! which is equivalent to: : \int x^n e^ \,\textx = \frac \left ( x^ne^ - n \int x^ e^ \,\textx \right ). \! Another alternative way in which the derivation could be done by integrating by parts: :I_n = \int x^ x e^ \,\textx, \! : u = x^ \text\ dv = e^ , : \frac \ = nx^ \text\ v = \frac\ : I_n = \frac\ - \int nx^\ \frac\ \textx\ : I_n = \frac\ - \frac\ \int x^ e^ \ \textx\ Remember: : I_ = \int x^ e^ \ \textx\ :\therefore\ I_n = \frac\ - \frac\ I_ which gives the reduction formula when substituting back: : I_n = \frac \left ( x^ne^ - n I_ \right ) , \,\! which is equivalent to: : \int x^n e^ \,\textx = \frac \left ( x^ne^ - n \int x^ e^ \,\textx \right ). \!


Tables of integral reduction formulas


Rational functions

The following integrals contain: *Factors of the
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\sqrt\,\! *Linear factors \,\! and the linear radical \sqrt\,\! * Quadratic factors x^2+a^2\,\! *Quadratic factors x^2-a^2\,\!, for x>a\,\! *Quadratic factors a^2-x^2\,\!, for x *( Irreducible) quadratic factors ax^2+bx+c\,\! *Radicals of irreducible quadratic factors \sqrt\,\! note that by the laws of indices: :I_ = I_ =\int \frac\,\textx = \int \frac\,\textx\,\!


Transcendental functions

The following integralshttp://www.sosmath.com/tables/tables.html -> Indefinite integrals list contain: *Factors of sine *Factors of cosine *Factors of sine and cosine products and quotients *Products/quotients of exponential factors and powers of ''x'' *Products of exponential and sine/cosine factors


References


Bibliography

*Anton, Bivens, Davis, Calculus, 7th edition. {{Integrals Integral calculus