Poisson Convergence Theorem

In probability theory, the law of rare events or Poisson limit theorem states that the Poisson distribution may be used as an approximation to the binomial distribution, under certain conditions. The theorem was named after Siméon Denis Poisson (1781–1840). A generalization of this theorem is Le Cam's theorem.

Theorem

Let $p_n$ be a sequence of real numbers in ,1 such that the sequence $n p_n$ converges to a finite limit $\lambda$. Then:
:$\lim_ p_n^k (1-p_n)^ = e^\frac$

Proofs

: $\begin \lim\limits_ p_n^k (1-p_n)^ &\simeq \lim_\frac \left(\frac\right)^k \left(1- \frac\right)^ \\ &= \lim_\frac\frac \left(1- \frac\right)^ \\ &= \lim_\frac \left(1-\frac\right)^ \end$.

Since
:$\lim_ \left(1-\frac\right)^ = e^$

and
:$\lim_ \left(1- \frac\right)^=1$

This leaves
:$p^k (1-p)^ \simeq \frac.$

Alternative proof

Using Stirling's approximation, we can write:
:$\begin p^k (1-p)^ &= \frac p^k (1-p)^ \\ &\simeq \frac p^k (1-p)^ \\ &= \sqrt\fracp^k (1-p)^. \end$

Letting $n \to \infty$ and $np = \lambda$:
:$\begin p^k (1-p)^ &\simeq \frac \\&= \frac \\&= \frac \\ &\simeq \frac . \end$

As $n \to \infty$, $\left(1-\frac\right)^n \to e^$ so:
:$\begin p^k (1-p)^ &\simeq \frac \\&= \frac \end$

Ordinary generating functions

It is also possible to demonstrate the theorem through the use of ordinary generating functions of the binomial distribution:
:
G_\operatorname(x;p,N)
\equiv \sum_^N \left \binom p^k (1-p)^ \rightx^k
= \Big 1 + (x-1)p \BigN

by virtue of the binomial theorem. Taking the limit $N \rightarrow \infty$ while keeping the product $pN\equiv\lambda$ constant, we find
:
\lim_ G_\operatorname(x;p,N)
= \lim_ \left 1 + \frac \rightN
= \mathrm^
= \sum_^ \left \frac \rightx^k

which is the OGF for the Poisson distribution. (The second equality holds due to the definition of the exponential function.)

See also

*De Moivre–Laplace theorem
*Le Cam's theorem

References

{{Reflist

Articles containing proofs
Probability theorems