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In mathematics, the Mazur–Ulam theorem states that if V and W are
normed space In mathematics, a normed vector space or normed space is a vector space over the real or complex numbers, on which a norm is defined. A norm is the formalization and the generalization to real vector spaces of the intuitive notion of "lengt ...
s over R and the mapping :f\colon V\to W is a surjective
isometry In mathematics, an isometry (or congruence, or congruent transformation) is a distance-preserving transformation between metric spaces, usually assumed to be bijective. The word isometry is derived from the Ancient Greek: ἴσος ''isos'' mea ...
, then f is
affine Affine may describe any of various topics concerned with connections or affinities. It may refer to: * Affine, a Affinity_(law)#Terminology, relative by marriage in law and anthropology * Affine cipher, a special case of the more general substi ...
. It was proved by Stanisław Mazur and
Stanisław Ulam Stanisław Marcin Ulam (; 13 April 1909 – 13 May 1984) was a Polish-American scientist in the fields of mathematics and nuclear physics. He participated in the Manhattan Project, originated the Teller–Ulam design of thermonuclear weapo ...
in response to a question raised by
Stefan Banach Stefan Banach ( ; 30 March 1892 – 31 August 1945) was a Polish mathematician who is generally considered one of the 20th century's most important and influential mathematicians. He was the founder of modern functional analysis, and an origina ...
. For strictly convex spaces the result is true, and easy, even for isometries which are not necessarily surjective. In this case, for any u and v in V, and for any t in ,1/math>, write r=\, u-v\, _V=\, f(u)-f(v)\, _W and denote the closed ball of radius around by \bar B(v,R). Then tu+(1-t)v is the unique element of \bar B(v,tr)\cap \bar B(u,(1-t)r), so, since f is injective, f(tu+(1-t)v) is the unique element of f\bigl(\bar B(v,tr)\cap \bar B(u,(1-t)r\bigr)= f\bigl(\bar B(v,tr)\bigr)\cap f\bigl(\bar B(u,(1-t)r\bigr)=\bar B\bigl(f(v),tr\bigr)\cap\bar B\bigl(f(u),(1-t)r\bigr), and therefore is equal to tf(u)+(1-t)f(v). Therefore f is an affine map. This argument fails in the general case, because in a normed space which is not strictly convex two tangent balls may meet in some flat convex region of their boundary, not just a single point.


See also

Aleksandrov–Rassias problem


References

* * * * Normed spaces Theorems in functional analysis {{mathanalysis-stub