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mathematics Mathematics is an area of knowledge that includes the topics of numbers, formulas and related structures, shapes and the spaces in which they are contained, and quantities and their changes. These topics are represented in modern mathematics ...
, the Carlson symmetric forms of elliptic integrals are a small canonical set of elliptic integrals to which all others may be reduced. They are a modern alternative to the
Legendre form In mathematics, the Legendre forms of elliptic integrals are a canonical set of three elliptic integrals to which all others may be reduced. Adrien-Marie Legendre, Legendre chose the name ''elliptic integrals'' because the second kind gives the ar ...
s. The Legendre forms may be expressed in terms of the Carlson forms and vice versa. The Carlson elliptic integrals are: R_F(x,y,z) = \tfrac\int_0^\infty \frac R_J(x,y,z,p) = \tfrac\int_0^\infty \frac R_C(x,y) = R_F(x,y,y) = \tfrac \int_0^\infty \frac R_D(x,y,z) = R_J(x,y,z,z) = \tfrac \int_0^\infty \frac Since R_C and R_D are special cases of R_F and R_J, all elliptic integrals can ultimately be evaluated in terms of just R_F and R_J. The term ''symmetric'' refers to the fact that in contrast to the Legendre forms, these functions are unchanged by the exchange of certain subsets of their arguments. The value of R_F(x,y,z) is the same for any permutation of its arguments, and the value of R_J(x,y,z,p) is the same for any permutation of its first three arguments. The Carlson elliptic integrals are named after Bille C. Carlson (1924-2013).


Relation to the Legendre forms


Incomplete elliptic integrals

Incomplete elliptic integrals can be calculated easily using Carlson symmetric forms: :F(\phi,k)=\sin\phi R_F\left(\cos^2\phi,1-k^2\sin^2\phi,1\right) :E(\phi,k)=\sin\phi R_F\left(\cos^2\phi,1-k^2\sin^2\phi,1\right) -\tfrack^2\sin^3\phi R_D\left(\cos^2\phi,1-k^2\sin^2\phi,1\right) :\Pi(\phi,n,k)=\sin\phi R_F\left(\cos^2\phi,1-k^2\sin^2\phi,1\right)+ \tfracn\sin^3\phi R_J\left(\cos^2\phi,1-k^2\sin^2\phi,1,1-n\sin^2\phi\right) (Note: the above are only valid for -\frac2\le\phi\le\frac2 and 0\le k^2\sin^2\phi\le1)


Complete elliptic integrals

Complete elliptic integrals can be calculated by substituting φ = π: :K(k)=R_F\left(0,1-k^2,1\right) :E(k)=R_F\left(0,1-k^2,1\right)-\tfrack^2 R_D\left(0,1-k^2,1\right) :\Pi(n,k)=R_F\left(0,1-k^2,1\right)+\tfracn R_J \left(0,1-k^2,1,1-n\right)


Special cases

When any two, or all three of the arguments of R_F are the same, then a substitution of \sqrt = u renders the integrand rational. The integral can then be expressed in terms of elementary transcendental functions. :R_(x,y) = R_(x,y,y) = \frac \int _^ \frac = \int _^ \frac = \begin \frac, & x < y \\ \frac, & x = y \\ \frac, & x > y \\ \end Similarly, when at least two of the first three arguments of R_J are the same, :R_(x,y,y,p) = 3 \int _^ \frac = \begin \frac (R_(x,y) - R_(x,p)), & y \ne p \\ \frac \left( R_(x,y) - \frac \sqrt\right), & y = p \ne x \\ \frac, &y = p = x \\ \end


Properties


Homogeneity

By substituting in the integral definitions t = \kappa u for any constant \kappa, it is found that :R_F\left(\kappa x,\kappa y,\kappa z\right)=\kappa^R_F(x,y,z) :R_J\left(\kappa x,\kappa y,\kappa z,\kappa p\right)=\kappa^R_J(x,y,z,p)


Duplication theorem

:R_F(x,y,z)=2R_F(x+\lambda,y+\lambda,z+\lambda)= R_F\left(\frac,\frac,\frac\right), where \lambda=\sqrt\sqrt+\sqrt\sqrt+\sqrt\sqrt. :\beginR_(x,y,z,p) & = 2 R_(x + \lambda,y + \lambda,z + \lambda,p + \lambda) + 6 R_(d^,d^ + (p - x) (p - y) (p - z)) \\ & = \frac R_\left( \frac,\frac,\frac,\frac\right) + 6 R_(d^,d^ + (p - x) (p - y) (p - z)) \end where d = (\sqrt + \sqrt) (\sqrt + \sqrt) (\sqrt + \sqrt) and \lambda =\sqrt\sqrt+\sqrt\sqrt+\sqrt\sqrt


Series Expansion

In obtaining a Taylor series expansion for R_ or R_ it proves convenient to expand about the mean value of the several arguments. So for R_, letting the mean value of the arguments be A = (x + y + z)/3, and using homogeneity, define \Delta x, \Delta y and \Delta z by :\beginR_(x,y,z) & = R_(A (1 - \Delta x),A (1 - \Delta y),A (1 - \Delta z)) \\ & = \frac R_(1 - \Delta x,1 - \Delta y,1 - \Delta z) \end that is \Delta x = 1 - x/A etc. The differences \Delta x, \Delta y and \Delta z are defined with this sign (such that they are ''subtracted''), in order to be in agreement with Carlson's papers. Since R_(x,y,z) is symmetric under permutation of x, y and z, it is also symmetric in the quantities \Delta x, \Delta y and \Delta z. It follows that both the integrand of R_ and its integral can be expressed as functions of the elementary symmetric polynomials in \Delta x, \Delta y and \Delta z which are :E_ = \Delta x + \Delta y + \Delta z = 0 :E_ = \Delta x \Delta y + \Delta y \Delta z + \Delta z \Delta x :E_ = \Delta x \Delta y \Delta z Expressing the integrand in terms of these polynomials, performing a multidimensional Taylor expansion and integrating term-by-term... :\beginR_(x,y,z) & = \frac \int _^\frac dt \\ & = \frac \int _^\left( \frac - \frac + \frac + \frac - \frac + O(E_) + O(\Delta^)\right) dt \\ & = \frac \left( 1 - \frac E_ + \frac E_ + \frac E_^ - \frac E_ E_ + O(E_) + O(\Delta^)\right) \end The advantage of expanding about the mean value of the arguments is now apparent; it reduces E_ identically to zero, and so eliminates all terms involving E_ - which otherwise would be the most numerous. An ascending series for R_ may be found in a similar way. There is a slight difficulty because R_ is not fully symmetric; its dependence on its fourth argument, p, is different from its dependence on x, y and z. This is overcome by treating R_ as a fully symmetric function of ''five'' arguments, two of which happen to have the same value p. The mean value of the arguments is therefore taken to be :A = \frac and the differences \Delta x, \Delta y \Delta z and \Delta p defined by :\beginR_(x,y,z,p) & = R_(A (1 - \Delta x),A (1 - \Delta y),A (1 - \Delta z),A (1 - \Delta p)) \\ & = \frac R_(1 - \Delta x,1 - \Delta y,1 - \Delta z,1 - \Delta p) \end The elementary symmetric polynomials in \Delta x, \Delta y, \Delta z, \Delta p and (again) \Delta p are in full :E_ = \Delta x + \Delta y + \Delta z + 2 \Delta p = 0 :E_ = \Delta x \Delta y + \Delta y \Delta z + 2 \Delta z \Delta p + \Delta p^ + 2 \Delta p \Delta x + \Delta x \Delta z + 2 \Delta y \Delta p :E_ = \Delta z \Delta p^ + \Delta x \Delta p^ + 2 \Delta x \Delta y \Delta p + \Delta x \Delta y \Delta z + 2 \Delta y \Delta z \Delta p + \Delta y \Delta p^ + 2 \Delta x \Delta z \Delta p :E_ = \Delta y \Delta z \Delta p^ + \Delta x \Delta z \Delta p^ + \Delta x \Delta y \Delta p^ + 2 \Delta x \Delta y \Delta z \Delta p :E_ = \Delta x \Delta y \Delta z \Delta p^ However, it is possible to simplify the formulae for E_, E_ and E_ using the fact that E_ = 0. Expressing the integrand in terms of these polynomials, performing a multidimensional Taylor expansion and integrating term-by-term as before... :\beginR_(x,y,z,p) & = \frac \int _^\frac dt \\ & = \frac \int _^\left( \frac - \frac + \frac + \frac + \frac + O(E_) + O(\Delta^)\right) dt \\ & = \frac \left( 1 - \frac E_ + \frac E_ + \frac E_^ - \frac E_ - \frac E_ E_ + \frac E_ + O(E_) + O(\Delta^)\right) \end As with R_, by expanding about the mean value of the arguments, more than half the terms (those involving E_) are eliminated.


Negative arguments

In general, the arguments x, y, z of Carlson's integrals may not be real and negative, as this would place a branch point on the path of integration, making the integral ambiguous. However, if the second argument of R_C, or the fourth argument, p, of R_J is negative, then this results in a
simple pole In complex analysis (a branch of mathematics), a pole is a certain type of singularity of a complex-valued function of a complex variable. In some sense, it is the simplest type of singularity. Technically, a point is a pole of a function if i ...
on the path of integration. In these cases the Cauchy principal value (finite part) of the integrals may be of interest; these are :\mathrm\; R_C(x, -y) = \sqrt\,R_C(x + y, y), and :\begin\mathrm\; R_(x,y,z,-p) & = \frac \\ & = \frac \end where :q = y + \frac. which must be greater than zero for R_(x,y,z,q) to be evaluated. This may be arranged by permuting x, y and z so that the value of y is between that of x and z.


Numerical evaluation

The duplication theorem can be used for a fast and robust evaluation of the Carlson symmetric form of elliptic integrals and therefore also for the evaluation of Legendre-form of elliptic integrals. Let us calculate R_F(x,y,z): first, define x_0=x, y_0=y and z_0=z. Then iterate the series :\lambda_n=\sqrt\sqrt+\sqrt\sqrt+\sqrt\sqrt, :x_=\frac, y_=\frac, z_=\frac until the desired precision is reached: if x, y and z are non-negative, all of the series will converge quickly to a given value, say, \mu. Therefore, :R_F\left(x,y,z\right)=R_F\left(\mu,\mu,\mu\right)=\mu^. Evaluating R_C(x,y) is much the same due to the relation :R_C\left(x,y\right)=R_F\left(x,y,y\right).


References and External links


B. C. Carlson, John L. Gustafson 'Asymptotic approximations for symmetric elliptic integrals' 1993 arXivB. C. Carlson 'Numerical Computation of Real Or Complex Elliptic Integrals' 1994 arXivB. C. Carlson 'Elliptic Integrals:Symmetric Integrals' in Chap. 19 of ''Digital Library of Mathematical Functions''. Release date 2010-05-07. National Institute of Standards and Technology.'Profile: Bille C. Carlson' in ''Digital Library of Mathematical Functions''. National Institute of Standards and Technology.
*{{Citation , last1=Press , first1=WH , last2=Teukolsky , first2=SA , last3=Vetterling , first3=WT , last4=Flannery , first4=BP , year=2007 , title=Numerical Recipes: The Art of Scientific Computing , edition=3rd , publisher=Cambridge University Press , publication-place=New York , isbn=978-0-521-88068-8 , chapter=Section 6.12. Elliptic Integrals and Jacobian Elliptic Functions , chapter-url=http://apps.nrbook.com/empanel/index.html#pg=309 * Fortran code from SLATEC for evaluatin
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Elliptic functions