Sign variation
Let be a finite sequence of real numbers. A ''sign variation'' or ''sign change'' in the sequence is a pair of indices such that and either or for all such that . In other words, a sign variation occurs in the sequence at each place where the signs change, when ignoring zeros. For studying the real roots of a polynomial, the number of sign variations of several sequences may be used. For Budan's theorem, it is the sequence of the coefficients. For the Budan–Fourier theorem, it is the sequence of values of the successive derivatives at a point. ForDescartes' rule of signs
All results described in this article are based on Descartes' rule of signs. If is a univariate polynomial with real coefficients, let us denote by the number of its positive real roots, counted with their multiplicity,This means that a root of multiplicity is counted as roots. and by the number of sign variations in the sequence of its coefficients. Descartes's rule of signs asserts that : is a nonnegative even integer. In particular, if , then one has .Budan's statement
Given a univariate polynomial with real coefficients, let us denote by the number of real roots, counted with their multiplicities, of in a half-open interval (with real numbers). Let us denote also by the number of sign variations in the sequence of the coefficients of the polynomial . In particular, one has with the notation of the preceding section. Budan's theorem is the following: : is a nonnegative even integer. As is non negative, this implies This is a generalization of Descartes' rule of signs, as, if one chooses sufficiently large, it is larger than all real roots of , and all the coefficients of are positive, that is Thus and which makes Descartes' rule of signs a special case of Budan's theorem. As for Descartes' rule of signs, if one has This means that, if one has a "zero-root test" and a "one-root test".Examples
1. Given the polynomial and the open interval , one has : Thus, and Budan's theorem asserts that the polynomial has either two or zero real roots in the open interval 2. With the same polynomial one has : Thus, and Budan's theorem asserts that the polynomial has no real root in the open interval This is an example of the use of Budan's theorem as a zero-root test.Fourier's statement
Fourier's theorem on polynomial real roots, also called Fourier–Budan theorem or Budan–Fourier theorem (sometimes just Budan's theorem) is exactly the same as Budan's theorem, except that, for and , the sequence of the coefficients of is replaced by the sequence of the derivatives of at . Each theorem is a corollary of the other. This results from the Taylor expansion : of the polynomial at , which implies that the coefficient of in is the quotient of by , a positive number. Thus the sequences considered in Fourier's theorem and in Budan's theorem have the same number of sign variations. This strong relationship between the two theorems may explain the priority controversy that occurred in 19th century, and the use of several names for the same theorem. In modern usage, for computer computation, Budan's theorem is generally preferred since the sequences have much larger coefficients in Fourier's theorem than in Budan's, because of the factorial factor.Proof
As each theorem is a corollary of the other, it suffices to prove Fourier's theorem. Thus, consider a polynomial , and an interval . When the value of increases from to , the number of sign variations in the sequence of the derivatives of may change only when the value of pass through a root of or one of its derivatives. Let us denote by either the polynomial or any of its derivatives. For any root of multiplicity of , this polynomial is well approximated near by for some constant . Moreover, for , its th derivative is approximated by It follows that, in the sequence formed by and its first derivatives, there are sign variations for and zero for . This shows that, when increases and passes through a root of of multiplicity , then the number of sign variations in the sequence of the derivative decreases by . Now, for , let be a root of the th derivative of , which is not a root of There are two cases to be considered. If the multiplicity of the root is even, then and keep a constant sign when pass through . This implies that the number of sign of variation in the sequence of derivatives decrease by the even number . On the other hand, if is odd, changes of sign at , while does not. There are thus sign variations. Thus, when pass through , the number of sign variation decrease either of or , which are nonnegative even numbers in each case.History
The problem of counting and locating the real roots of a polynomial started to be systematically studied only in the beginning of the 19th century. In 1807, François Budan de Boislaurent discovered a method for extending Descartes' rule of signs—valid for the interval —to any interval.Use in 19th century
Budan's and Fourier's theorems were soon considered of a great importance, although they do not solve completely the problem of counting the number of real roots of a polynomial in an interval. This problem was completely solved in 1827 bySee also
* Properties of polynomial roots * Root-finding algorithmReferences
External links
{{MacTutor, title=Budan de Boislaurent Mathematical theorems Root-finding algorithms Real algebraic geometry