Definition
Let be a plane triangle and let be the trilinear coordinates of an arbitrary point in the plane of triangle . A straight line in the plane of triangle whose equation in trilinear coordinates has the form : where the point with trilinear coordinates is a triangle center, is a central line in the plane of triangle relative to the triangle .Central lines as trilinear polars
The geometric relation between a central line and its associated triangle center can be expressed using the concepts of trilinear polars and isogonal conjugates. Let ''X'' = ( ''u'' ( ''a'', ''b'', ''c'' ) : ''v'' ( ''a'', ''b'', ''c'' ) : ''w'' ( ''a'', ''b'', ''c'' ) ) be a triangle center. The line whose equation is : ''x'' / ''u'' ( ''a'', ''b'', ''c'' ) + ''y'' / ''v'' ( ''a'', ''b'', ''c'' ) ''y'' + ''z'' / ''w'' ( ''a'', ''b'', ''c'' ) = 0 is theConstruction of central lines
Let ''X'' be any triangle center of the triangle ''ABC''. *Draw the lines ''AX'', ''BX'' and ''CX'' and their reflections in the internal bisectors of the angles at the vertices ''A'', ''B'', ''C'' respectively. *The reflected lines are concurrent and the point of concurrence is the isogonal conjugate ''Y'' of ''X''. *Let the cevians ''AY'', ''BY'', ''CY'' meet the opposite sidelines of triangle ''ABC'' at ''A' '', ''B' '', ''C' '' respectively. The triangle ''A''Some named central lines
Let ''X''''n'' be the ''n'' th triangle center inCentral line associated with ''X''1, the incenter: Antiorthic axis
The central line associated with the incenter ''X''1 = ( 1 : 1 : 1 ) (also denoted by ''I'') is : ''x'' + ''y'' + ''z'' = 0. This line is the antiorthic axis of triangle ''ABC''. *The isogonal conjugate of the incenter of a triangle ''ABC'' is the incenter itself. So the antiorthic axis, which is the central line associated with the incenter, is the axis of perspectivity of the triangle ''ABC'' and itsCentral line associated with ''X''2, the centroid: Lemoine axis
The trilinear coordinates of the centroid ''X''2 (also denoted by ''G'') of triangle ''ABC'' are ( 1 / ''a'' : 1 / ''b'' : 1 / ''c'' ). So the central line associated with the centroid is the line whose trilinear equation is : ''x / a'' + ''y / b'' + ''z / c'' = 0. This line is the Lemoine axis, also called the Lemoine line, of triangle ''ABC''. *The isogonal conjugate of the centroid ''X''2 is the symmedian point ''X''6 (also denoted by ''K'') having trilinear coordinates ( ''a'' : ''b'' : ''c'' ). So the Lemoine axis of triangle ''ABC'' is the trilinear polar of the symmedian point of triangle ''ABC''. *The tangential triangle of triangle ''ABC'' is the triangle ''TATBTC'' formed by the tangents to the circumcircle of triangle ''ABC'' at its vertices. Triangle ''ABC'' and its tangential triangle are in perspective and the axis of perspectivity is the Lemoine axis of triangle ''ABC''.Central line associated with ''X''3, the circumcenter: Orthic axis
The trilinear coordinates of the circumcenter ''X''3 (also denoted by ''O'') of triangle ''ABC'' are ( cos ''A'' : cos ''B'' : cos ''C'' ). So the central line associated with the circumcenter is the line whose trilinear equation is : ''x'' cos ''A'' + ''y'' cos ''B'' + ''z'' cos ''C'' = 0. This line is the orthic axis of triangle ''ABC''. *The isogonal conjugate of the circumcenter ''X''6 is the orthocenter ''X''4 (also denoted by ''H'') having trilinear coordinates ( sec ''A'' : sec ''B'' : sec ''C'' ). So the orthic axis of triangle ''ABC'' is the trilinear polar of the orthocenter of triangle ''ABC''. The orthic axis of triangle ''ABC'' is the axis of perspectivity of triangle ''ABC'' and its orthic triangle ''HAHBHC''.Central line associated with ''X''4, the orthocenter
The trilinear coordinates of the orthocenter ''X''4 (also denoted by ''H'') of triangle ''ABC'' are ( sec ''A'' : sec ''B'' : sec ''C'' ). So the central line associated with the circumcenter is the line whose trilinear equation is : ''x'' sec ''A'' + ''y'' sec ''B'' + ''z'' sec ''C'' = 0. *The isogonal conjugate of the orthocenter of a triangle is the circumcenter of the triangle. So the central line associated with the orthocenter is the trilinear polar of the circumcenter.Central line associated with ''X''5, the nine-point center
The trilinear coordinates of the nine-point center ''X''5 (also denoted by ''N'') of triangle ''ABC'' are ( cos ( ''B'' − ''C'' ) : cos ( ''C'' − ''A'' ) : cos ( ''A'' − ''B'' ) ). So the central line associated with the nine-point center is the line whose trilinear equation is : ''x'' cos ( ''B'' − ''C'' ) + ''y'' cos ( ''C'' − ''A'' ) + ''z'' cos ( ''A'' − ''B'' ) = 0. *The isogonal conjugate of the nine-point center of triangle ''ABC'' is the Kosnita point ''X''54 of triangle ''ABC''. So the central line associated with the nine-point center is the trilinear polar of the Kosnita point. *The Kosnita point is constructed as follows. Let ''O'' be the circumcenter of triangle ''ABC''. Let ''OA'', ''OB'', ''OC'' be the circumcenters of the triangles ''BOC'', ''COA'', ''AOB'' respectively. The lines ''AOA'', ''BOB'', ''COC'' are concurrent and the point of concurrence is the Kosnita point of triangle ''ABC''. The name is due to J Rigby.Central line associated with ''X''6, the symmedian point : Line at infinity
The trilinear coordinates of the symmedian point ''X''6 (also denoted by ''K'') of triangle ''ABC'' are ( ''a'' : ''b'' : ''c'' ). So the central line associated with the symmedian point is the line whose trilinear equation is : ''a'' ''x'' + ''b'' ''y'' + ''c'' ''z'' =0. *This line is the line at infinity in the plane of triangle ''ABC''. *The isogonal conjugate of the symmedian point of triangle ''ABC'' is the centroid of triangle ''ABC''. Hence the central line associated with the symmedian point is the trilinear polar of the centroid. This is the axis of perspectivity of the triangle ''ABC'' and its medial triangle.Some more named central lines
Euler line
Euler line of triangle ''ABC'' is the line passing through the centroid, the circumcenter, the orthocenter and the nine-point center of triangle ''ABC''. The trilinear equation of the Euler line is : ''x'' sin 2''A'' sin ( ''B'' − ''C'' ) + ''y'' sin 2''B'' sin ( ''C'' − ''A'' ) + ''z'' sin 2''C'' sin ( ''C'' − ''A'' ) = 0. This is the central line associated with the triangle center ''X''647.Nagel line
''Nagel line'' of triangle ''ABC'' is the line passing through the centroid, the incenter, the Spieker center and the Nagel point of triangle ''ABC''. The trilinear equation of the Nagel line is : ''x'' ''a'' ( ''b'' − ''c'' ) + ''y'' ''b'' ( ''c'' − ''a'' ) + ''z'' ''c'' ( ''a'' − ''b'' ) = 0. This is the central line associated with the triangle center ''X''649.Brocard axis
The Brocard axis of triangle ''ABC'' is the line through the circumcenter and the symmedian point of triangle ''ABC''. Its trilinear equation is : ''x'' sin (''B'' − ''C'' ) + ''y'' sin ( ''C'' − ''A'' ) + ''z'' sin ( ''A'' − ''B'' ) = 0. This is the central line associated with the triangle center ''X''523.See also
* Trilinear polarity *References
{{reflist, 2 Straight lines defined for a triangle